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题目要求：

People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red, the middle 2 digits for Green, and the last 2 digits for Blue. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.

Input

Each input file contains one test case which occupies a line containing the three decimal color values.

Output

For each test case you should output the Mars RGB value in the following format: first output “#”, then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a “0” to the left.

Sample Input

15 43 71 Sample Output

#123456

参考代码：

#include  
   
    char radix[13] = {
  '0','1','2','3','4','5','6','7','8','9','A','B','C'};int main(){    int r,g,b;    scanf("%d%d%d",&r,&g,&b);    printf("#");    printf("%c%c",radix[r/13],radix[r%13]);    printf("%c%c",radix[g/13],radix[g%13]);    printf("%c%c",radix[b/13],radix[b%13]);    return 0;}
   

还有一种答案，本人苦苦无法找寻错误，望各位看官能够给予建议：

#include 
   
    using namespace std;int main(){   for(int j=0;j<3;j++)   {       int a;       int i=0;       int b[3] = {
  0};       cin >>a;       if(a==0)       {           b[i] = 0;           i = 1;       }       while(a)       {           b[i] = a%13;           a = a/13;           i++;       }       if(j==0)           cout <<"#";       for(int j=0;j
    
     =0)&&(b[i-1-j]<10))               cout << b[i-1-j];           else           {               switch(b[i-1-j])               {                   case 10:cout <<"A";break;                   case 11:cout <<"B";break;                   case 12:cout <<"C";break;               }            }        }   }   return 0;}
    
   

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